ShiftLR ParsersImplementationsIR FormsRuntime Environment and activation recordsdoesnt matter if prefix is T or NTUsing GNF we can convertLeft recursive grammar toright recursivefirst(a1) ∩ first(a2)first(a1) ∩ follow(X)L to R parseRMDallthese parsers have the abilityto parse some ambiguous grammarBUP pushes tokens into stackAnd then decides if it can reduce the TOSstring gets accepted when stack has only Start symbol, and remaining inp symbol is $Add LR(O) items to Suntil there are no more to add.expected to see something that A reduces toOfstored in the stackSince SLR doesn't reduce blindly, conflict in LR(0) might not be theretake care of $while seeing reduced statesin SLR table (& while parsing), reduce only where (next) inp symb comes in follow (of TOS)anything w/ a reducedeven .∈orindicate a severe internal inconsistency within the compiler itselfNon-Recoverable Impact unlike other stagesconnonicalnumber of shift entries in SLR(1) and LALR(1) is equalLR(1) item :An item 𝑋 → 𝛼. 𝛽, a• parser is looking to reduce to X if next input symbol a• It has already seen 𝛼 (also 𝛼 is on top of stack)• Expects to find string derived from 𝛽 in the next inputIn an LR(1) machine with a shift/reduce conflict, we should shift if the priority of the rule islower than the priority of the incoming symbol, or if the priorities are the same and are bothright associative.Lookahead means first() of immediate part of variable whose closure has been putSome grammars can be LR(1) but not LALRRR conflict in LALR, but none in LR1📍[[GT]]AST omitted the syntactic details of parse tree but not semantic.LR1 grammar exists for all DCFGOnly(Parent is taking value from child attribute)&Both(child is taking value from Parent/sibling)Follow(only if 1st contains ∈)would cause ∞ loopambiguity in decision-makingpostpones the decision about whichproduction to use until enough inputhas been seen to make an informedchoice🌐https://www.youtube.com/watch?v=0q1BEXFUaBEsimple & SynthesizedLeft-to-rightattr. val.∈ free LL1 is also SLR(1)∈ is added to First of Xonly if all Y's in X -> Y1Y2...Yk have ∈RDPgeneralRDPBruteforceNobecause of stack spaceNon recursive or tableproceduralE → T | T ∗ ET → int | int ∗ T | (E)inherited attributes of Xidepends on any attributes ofX1, X2,...., X_{i-1} but ONLY inherited attributes ofparent Afor any sentential formthis is just next input symbol, not lookaheadlookahead comes into play only when the dot is at the end of a production,signaling a reduce action.